Chapter 0 – Steady-State Hydraulics
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Surge Analysis and the Wave Plan Method
Supplementary Material: Example Problems and Solutions
Chapter 0 – Problem 0.18
0.18 What is the resultant steady-state flowrate if there is a partially-throttled gate valve with a minor loss coefficient of 20 located close to reservoir B in the pipeline described in the previous question 0.17 ?
The energy equation described in the previous question is altered by adding the minor loss term associated with the partially-throttled gate valve:
E A + E P – ΔH – kV 2 /(2g) = E B , where V is the pipe flow velocity and k is the minor loss coefficient of the partially-throttled gate valve.
If A is the pipe cross sectional area, then V = Q/A. A = 0.196 m 2 , for the given pipe diameter of 500 mm.
50 + 10.194/Q – (10.67 LQ 1.852 )/(C 1.852 D 4.87 ) – 20*Q 2 / (2g A 2 ) = 100
Solve for Q iteratively: Q = 0.165 m 3 /s
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